3x/(x+2)+6/x=12/(x^2+2x)

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Solution for 3x/(x+2)+6/x=12/(x^2+2x) equation:


D( x )

x+2 = 0

x = 0

x^2+2*x = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x = 0

x = 0

x^2+2*x = 0

x^2+2*x = 0

x^2+2*x = 0

DELTA = 2^2-(0*1*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)-2)/(1*2) or x = (-4^(1/2)-2)/(1*2)

x = 0 or x = -2

x in (-oo:-2) U (-2:0) U (0:+oo)

(3*x)/(x+2)+6/x = 12/(x^2+2*x) // - 12/(x^2+2*x)

(3*x)/(x+2)-(12/(x^2+2*x))+6/x = 0

(3*x)/(x+2)-12*(x^2+2*x)^-1+6/x = 0

(3*x)/(x+2)-12/(x^2+2*x)+6/x = 0

x^2+2*x = 0

x^2+2*x = 0

x*(x+2) = 0

x+2 = 0 // - 2

x = -2

x*(x+2) = 0

(3*x)/(x+2)-12/(x*(x+2))+6/x = 0

(3*x*x)/(x*(x+2))-12/(x*(x+2))+(6*(x+2))/(x*(x+2)) = 0

6*(x+2)+3*x*x-12 = 0

3*x^2+6*x-12+12 = 0

3*x^2+6*x = 0

3*x^2+6*x = 0

3*x*(x+2) = 0

x+2 = 0 // - 2

x = -2

3*x*(x+2) = 0

(3*x*(x+2))/(x*(x+2)) = 0

(3*x*(x+2))/(x*(x+2)) = 0 // * x*(x+2)

3*x*(x+2) = 0

( 3*x )

3*x = 0 // : 3

x = 0

( x+2 )

x+2 = 0 // - 2

x = -2

x in { 0}

x in { -2}

x belongs to the empty set

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